# What is the area of the region between the graphs of y=x^2 and y=-x from x=0 to x=2?

2 months ago

Guest #4339
2 months ago
2/3 units
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Find (f o g)(2) and (f+g)(2) when f(x)=1/x and g(x)=4x+9
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(f o g) (2)= 1/17 and (f+g) (2)= 17.5
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What is the null hypothesis if we want to test the hypothesis that the mean score on campus 1 is higher than on campus 2? h0: Âµ1 = 0?
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Îœ1 <= Î¼2
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Median number for 100 110 120 125 140 150 160
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Rolando had $120,000 in a cd at big bucks bank which just failed. If the fdic insurance limit per depositor, per bank is$250,000 how much will rosado get back
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the angle of the first hill of a roller coaster is 55 degrees. if the length of the track from the beginning of the ascent to the highest point is 98 feet, what is the height if the roller coaster when it reaches the top of the first hill?
Solution 1
The height of the ascent will be given by:
sinÂ Î¸=opposite/hypotenuse
Î¸=55Â°
opposite=h
hypotenuse=98 ft
thus the height will be:
sin 55=h/98
solving for h we get:
h=98Ã—sin55
h=80.28 ft
Thus the height is 80.28 ft
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A circle has a radius of 6x^9y^5 cm, what is the area of this circle in square centimeters
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Nina wants to put color tiles on a square. 3 color tiles fit across the top of the square. How many rows and columns of square will Nina need? How many color tiles will she use in all?
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The area is a square.Â If she uses 3 tiles to fit length-wise, she will need 3 tiles to fit width-wise.

Total tiles needed = 3 x 3 = 9 tiles.

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Which of the following graphs could bw the graph of the function f(x)=.03x^2(x^2-25)
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ItÅ› A

Step-by-step explanation:

Solution 2

A

Step-by-step explanation:

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Suppose you have an isosceles triangle, and each of the equal sides has a length of 1 foot. suppose the angle formed by those two sides is 45^\circ. then the area of the triangle is
Solution 1
The triangle has a 45-deg angle.
The base angles are congruent and measure 67.5 deg.
The congruent sides measure 1 ft.
Use law of sines to find the length of the base.

Draw a height from the vertex of the 45-deg angle to the base.
Half of the base is 0.765 ft/2 = 0.383 ft

We can find the height of the triangle using the small triangles.

0.383^2 + h^2 = 1^2

h = 0.9239 ft

A = bh/2 = 0.765 * 0.9239/2 ft^2

A = 0.354 ft^2
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In rotation, which point is moved the greatest?
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The point furthest from the centre of rotation.

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