The height reached by amal's rocket was 1/4 of the height reached by min's rocket. Amal's rocket REAched a height of 15 meters. Which equation could be used to find the height reached by min's rocket
2 months ago
Solution 1
2 months ago
To solve this problem you must keep on min the information given in the problem shown above:
1- You have that
- The height reached by amal's rocket was 1/4 of the height reached by min's rocket.
- Amal's rocket REAched a height of 15 meters.
2. Therefore, let's call "x" to the height reached by min's rocket. Then, you have:
(1/4)x=15
x/4=15
Which equation could be used to find the height reached by min's rocket?
The answer is: x/4=15
1- You have that
- The height reached by amal's rocket was 1/4 of the height reached by min's rocket.
- Amal's rocket REAched a height of 15 meters.
2. Therefore, let's call "x" to the height reached by min's rocket. Then, you have:
(1/4)x=15
x/4=15
Which equation could be used to find the height reached by min's rocket?
The answer is: x/4=15
📚 Related Questions
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Marina correctly simplified the expression (-4a^-2 b^4)/(8a^-6b^-3) assuming that a does not equal 0 and b does not equal 0. Her simplified expression is below. -1/2a^4b^
The exponent of the variable b in Marina’s solution should be...
Solution 1
For this case we have the following expression:
(-4a ^ -2 b ^ 4) / (8a ^ -6b ^ -3)
We can rewrite the expression using properties of exponents.
We have then:
(-4/8) * ((a ^ (- 2 - (- 6))) (b ^ (4 - (- 3))))
Rewriting we have:
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Answer:
The exponent of the variable b in Marina's solution should be 7
(-4a ^ -2 b ^ 4) / (8a ^ -6b ^ -3)
We can rewrite the expression using properties of exponents.
We have then:
(-4/8) * ((a ^ (- 2 - (- 6))) (b ^ (4 - (- 3))))
Rewriting we have:
(-2/4) * ((a ^ (- 2 + 6)) (b ^ (4 + 3)))
(-1/2) * ((a ^ 4) (b ^ 7))
-1 / 2a ^ 4b ^ 7
Answer:
The exponent of the variable b in Marina's solution should be 7
Solution 2
Answer:
7 is correct!
Step-by-step explanation:
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Which of the following pairs of numbers contain like fractions? A. 3
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D. 31
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and 43
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Solution 1
C. 5/6 and 10/12
If you simplify 10/12 but the greatest common factor of 10 and 12, which is 2, you get the answer of 5/6. Now if you multiple 5/6 by two, you get 10/12. Either way, both fractions are clearly equivalent.
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A teacher asked her students to divide a large number by 50. • Aslan divided the number by 50.
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• Jack divided the number by 10 and then divided the answer he got by 40.
Who among these got the correct answer assuming they did NOT make mistakes in division?
Solution 1
Answer:
c
Step-by-step explanation:
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The football team is running a jackpot in which the prize will start at $2500 for the first game, and then increase $500 each game if there is no winner. If there are no winners, find the value of the jackpot at the end of their 16-game season.
Solution 1
The value of the jackpot at the end of the 16-game season will be $10,000.
What is an expression?
An expression contains one or more terms with addition, subtraction, multiplication, and division.
We always combine the like terms in an expression when we simplify.
We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.
Example:
1 + 3x + 4y = 7 is an expression.
3 + 4 is an expression.
2 x 4 + 6 x 7 – 9 is an expression.
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We have,
The jackpot prize starts at $2500 for the first game and increases by $500 for each game if there is no winner.
For the second game,
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Continuing in this pattern, the prize for the 16th game will be:
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Therefore,
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Solution 2
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A catapult launches a boulder with an upward velocity of 184 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h= -16t^2 + 184t + 20. How long does it take the boulder to reach its maximum height? What is the boulder's maximum hieght
Solution 1
For this case we have the following equation:
h = -16t ^ 2 + 184t + 20
Deriving we have:
h '= -32t + 184
We equal zero and clear t:
-32t + 184 = 0
32t = 184
t = 184/32
t = 5.75 s
Then, the maximum height is given by:
h (5.75) = -16 * (5.75) ^ 2 + 184 * (5.75) + 20
h (5.75) = 549 feet
Answer:
It takes the boulder to reach its maximum height about:
t = 5.75 s
the boulder's maximum hieght is:
h (5.75) = 549 feet
h = -16t ^ 2 + 184t + 20
Deriving we have:
h '= -32t + 184
We equal zero and clear t:
-32t + 184 = 0
32t = 184
t = 184/32
t = 5.75 s
Then, the maximum height is given by:
h (5.75) = -16 * (5.75) ^ 2 + 184 * (5.75) + 20
h (5.75) = 549 feet
Answer:
It takes the boulder to reach its maximum height about:
t = 5.75 s
the boulder's maximum hieght is:
h (5.75) = 549 feet
Solution 2
Answer:
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A ball is thrown into the air with an upward velocity of 32 ft/s. Its height (h) in feet after t seconds is given by the function h= -16t^2 + 32t + 6. How long does it take the ball to reach its maximum height? What is the ball’s maximum height? Roun
Solution 1
For this case we have the following equation:
h = -16t ^ 2 + 32t + 6
Deriving we have:
h '= -32t + 32
We equal zero and clear t:
-32t + 32 = 0
32t = 32
t = 32/32
t = 1 s
Then, the maximum height is given by:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
It takes the ball to reach its maximum height about:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
h = -16t ^ 2 + 32t + 6
Deriving we have:
h '= -32t + 32
We equal zero and clear t:
-32t + 32 = 0
32t = 32
t = 32/32
t = 1 s
Then, the maximum height is given by:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
It takes the ball to reach its maximum height about:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
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