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2.50 g CuCl2 equals how many moles

2.50 g CuCl2 equals how many moles

2 months ago

Solution 1

Guest Guest #77
2 months ago
The molar mass of CuCl2 is 134.45 g/mol; therefore, you divide 2.5 g of CuCl2 by 134.45 g of CuCl2 leaving you with 0.019 moles

Solution 2

Guest Guest #78
2 months ago

Explanation:

Number of moles is defined as the mass of substance given in grams divided by the molar mass of substance.

It is given that mass of CuCl_{2} is 2.50 g and molar mass of CuCl_{2} is 134.45 g/mol.

Therefore, calculate number of moles as follows.

      Number of moles of CuCl_{2} = \frac{mass}{molar mass}

                                        = \frac{2.50 g}{134.45 g/mol}

                                         = 0.0186 mol

                                         = 0.019 mol (approx)

Thus, we can conclude that 2.50 g CuCl2 equals 0.019 moles (approx).                  

📚 Related Questions

Question
A chemical supply company sells a concentrated solution of aqueous h2so4 (molar mass 98 g mol−1 ) that is 50. percent h2so4 by mass. at 25°c, the density of the solution is 1.4 g ml−1 . what is the molarity of the h2so4 solution at 25°c?
Solution 1
Answer is: the molarity of the sulfuric acid is 7.14 M.
ω(H₂SO₄) = 50% ÷ 100% = 0.5.
d(H₂SO₄) = 1.4 g/mL.
V(H₂SO₄) = 100 mL ÷ 1000 mL/L = 0.1 L..
mr(H₂SO₄) = d(H₂SO₄) · V(H₂SO₄).
mr(H₂SO₄) = 1.4 g/mL · 100 mL.
mr(H₂SO₄) = 140 g.
m(H₂SO₄) = ω(H₂SO₄) · mr(H₂SO₄).
m(H₂SO₄) = 0.5 · 140 g.
m(H₂SO₄) = 70 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 70 g ÷ 98 g/mol.
n(H₂SO₄) = 0.714 mol.
c(H₂SO₄) = n(H₂SO₄) ÷ V(H₂SO₄).
c(H₂SO₄) = 0.714 mol ÷ 0.1 L.
C(H₂SO₄) = 7.14 M.
Question
Calculate the number of moles of naoh present in 11.2 ml of 2.50 m naoh solution
Solution 1
Let's review what is given in this problem.

The volume of the solution is 11.2 milliliters, which is 0.0112 liters (multiply 11.2 mL with 1 L / 1000 mL to get 0.0112).

The molar concentration is 2.5 M. This means that there are 2.5 moles of NaOH per liter in the solution.

Multiply the volume and the molar concentration to get the moles of NaOH in the solution.

\text{moles of NaOH} = 0.0112 \: \text{Liter} \times \dfrac{2.5 \: \text{moles}}{1 \: \text{Liter}}

The "Liter" will cancel out, leaving only moles.
After using a calculator (or computing by hand), you should get the following value:

0.028 \: \text{moles}

Since the given values were given with 3 significant figures, let's change this answer so there are 3 significant figures.

Thus, your final answer is 0.0280 \: \text{moles}

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